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2707\. Extra Characters in a String

Medium

You are given a **0-indexed** string `s` and a dictionary of words `dictionary`. You have to break `s` into one or more **non-overlapping** substrings such that each substring is present in `dictionary`. There may be some **extra characters** in `s` which are not present in any of the substrings.

Return _the **minimum** number of extra characters left over if you break up_ `s` _optimally._

**Example 1:**

**Input:** s = "leetscode", dictionary = ["leet","code","leetcode"]

**Output:** 1

**Explanation:** We can break s in two substrings: "leet" from index 0 to 3 and "code" from index 5 to 8. There is only 1 unused character (at index 4), so we return 1.

**Example 2:**

**Input:** s = "sayhelloworld", dictionary = ["hello","world"]

**Output:** 3

**Explanation:** We can break s in two substrings: "hello" from index 3 to 7 and "world" from index 8 to 12. The characters at indices 0, 1, 2 are not used in any substring and thus are considered as extra characters. Hence, we return 3.

**Constraints:**

*   `1 <= s.length <= 50`
*   `1 <= dictionary.length <= 50`
*   `1 <= dictionary[i].length <= 50`
*   `dictionary[i]` and `s` consists of only lowercase English letters
*   `dictionary` contains distinct words




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