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Kotlin-based LeetCode algorithm problem solutions, regularly updated
2762\. Continuous Subarrays
Medium
You are given a **0-indexed** integer array `nums`. A subarray of `nums` is called **continuous** if:
* Let `i`, `i + 1`, ..., `j` be the indices in the subarray. Then, for each pair of indices i <= i1, i2 <= j, 0 <= |nums[i1] - nums[i2]| <= 2.
Return _the total number of **continuous** subarrays._
A subarray is a contiguous **non-empty** sequence of elements within an array.
**Example 1:**
**Input:** nums = [5,4,2,4]
**Output:** 8
**Explanation:**
Continuous subarray of size 1: [5], [4], [2], [4].
Continuous subarray of size 2: [5,4], [4,2], [2,4].
Continuous subarray of size 3: [4,2,4].
Thereare no subarrys of size 4.
Total continuous subarrays = 4 + 3 + 1 = 8.
It can be shown that there are no more continuous subarrays.
**Example 2:**
**Input:** nums = [1,2,3]
**Output:** 6
**Explanation:**
Continuous subarray of size 1: [1], [2], [3].
Continuous subarray of size 2: [1,2], [2,3].
Continuous subarray of size 3: [1,2,3].
Total continuous subarrays = 3 + 2 + 1 = 6.
**Constraints:**
* 1 <= nums.length <= 105
* 1 <= nums[i] <= 109