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Kotlin-based LeetCode algorithm problem solutions, regularly updated
9\. Palindrome Number
Easy
Given an integer `x`, return `true` if `x` is palindrome integer.
An integer is a **palindrome** when it reads the same backward as forward. For example, `121` is palindrome while `123` is not.
**Example 1:**
**Input:** x = 121
**Output:** true
**Example 2:**
**Input:** x = -121
**Output:** false
**Explanation:** From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
**Example 3:**
**Input:** x = 10
**Output:** false
**Explanation:** Reads 01 from right to left. Therefore it is not a palindrome.
**Example 4:**
**Input:** x = -101
**Output:** false
**Constraints:**
* -231 <= x <= 231 - 1
**Follow up:** Could you solve it without converting the integer to a string?