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97\. Interleaving String

Medium

Given strings `s1`, `s2`, and `s3`, find whether `s3` is formed by an **interleaving** of `s1` and `s2`.

An **interleaving** of two strings `s` and `t` is a configuration where `s` and `t` are divided into `n` and `m` **non-empty** substrings respectively, such that:

*   s = s1 + s2 + ... + sn
*   t = t1 + t2 + ... + tm
*   `|n - m| <= 1`
*   The **interleaving** is s1 + t1 + s2 + t2 + s3 + t3 + ... or t1 + s1 + t2 + s2 + t3 + s3 + ...

**Note:** `a + b` is the concatenation of strings `a` and `b`.

**Example 1:**

![](https://assets.leetcode.com/uploads/2020/09/02/interleave.jpg)

**Input:** s1 = "aabcc", s2 = "dbbca", s3 = "aadbbcbcac"

**Output:** true

**Explanation:** One way to obtain s3 is: Split s1 into s1 = "aa" + "bc" + "c", and s2 into s2 = "dbbc" + "a". Interleaving the two splits, we get "aa" + "dbbc" + "bc" + "a" + "c" = "aadbbcbcac". Since s3 can be obtained by interleaving s1 and s2, we return true.

**Example 2:**

**Input:** s1 = "aabcc", s2 = "dbbca", s3 = "aadbbbaccc"

**Output:** false

**Explanation:** Notice how it is impossible to interleave s2 with any other string to obtain s3.

**Example 3:**

**Input:** s1 = "", s2 = "", s3 = ""

**Output:** true

**Constraints:**

*   `0 <= s1.length, s2.length <= 100`
*   `0 <= s3.length <= 200`
*   `s1`, `s2`, and `s3` consist of lowercase English letters.

**Follow up:** Could you solve it using only `O(s2.length)` additional memory space?




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