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Kotlin-based LeetCode algorithm problem solutions, regularly updated
1\. Two Sum
Easy
Given an array of integers `nums` and an integer `target`, return _indices of the two numbers such that they add up to `target`_.
You may assume that each input would have **_exactly_ one solution**, and you may not use the _same_ element twice.
You can return the answer in any order.
**Example 1:**
**Input:** nums = [2,7,11,15], target = 9
**Output:** [0,1]
**Output:** Because nums[0] + nums[1] == 9, we return [0, 1].
**Example 2:**
**Input:** nums = [3,2,4], target = 6
**Output:** [1,2]
**Example 3:**
**Input:** nums = [3,3], target = 6
**Output:** [0,1]
**Constraints:**
* 2 <= nums.length <= 104
* -109 <= nums[i] <= 109
* -109 <= target <= 109
* **Only one valid answer exists.**
**Follow-up:** Can you come up with an algorithm that is less than O(n2)
time complexity?