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g0001_0100.s0079_word_search.readme.md Maven / Gradle / Ivy

79\. Word Search

Medium

Given an `m x n` grid of characters `board` and a string `word`, return `true` _if_ `word` _exists in the grid_.

The word can be constructed from letters of sequentially adjacent cells, where adjacent cells are horizontally or vertically neighboring. The same letter cell may not be used more than once.

**Example 1:**

![](https://assets.leetcode.com/uploads/2020/11/04/word2.jpg)

**Input:** board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "ABCCED"

**Output:** true

**Example 2:**

![](https://assets.leetcode.com/uploads/2020/11/04/word-1.jpg)

**Input:** board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "SEE"

**Output:** true

**Example 3:**

![](https://assets.leetcode.com/uploads/2020/10/15/word3.jpg)

**Input:** board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "ABCB"

**Output:** false

**Constraints:**

*   `m == board.length`
*   `n = board[i].length`
*   `1 <= m, n <= 6`
*   `1 <= word.length <= 15`
*   `board` and `word` consists of only lowercase and uppercase English letters.

**Follow up:** Could you use search pruning to make your solution faster with a larger `board`?