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Kotlin-based LeetCode algorithm problem solutions, regularly updated
332\. Reconstruct Itinerary
Hard
You are given a list of airline `tickets` where tickets[i] = [fromi, toi]
represent the departure and the arrival airports of one flight. Reconstruct the itinerary in order and return it.
All of the tickets belong to a man who departs from `"JFK"`, thus, the itinerary must begin with `"JFK"`. If there are multiple valid itineraries, you should return the itinerary that has the smallest lexical order when read as a single string.
* For example, the itinerary `["JFK", "LGA"]` has a smaller lexical order than `["JFK", "LGB"]`.
You may assume all tickets form at least one valid itinerary. You must use all the tickets once and only once.
**Example 1:**
![](https://assets.leetcode.com/uploads/2021/03/14/itinerary1-graph.jpg)
**Input:** tickets = [["MUC","LHR"],["JFK","MUC"],["SFO","SJC"],["LHR","SFO"]]
**Output:** ["JFK","MUC","LHR","SFO","SJC"]
**Example 2:**
![](https://assets.leetcode.com/uploads/2021/03/14/itinerary2-graph.jpg)
**Input:** tickets = [["JFK","SFO"],["JFK","ATL"],["SFO","ATL"],["ATL","JFK"],["ATL","SFO"]]
**Output:** ["JFK","ATL","JFK","SFO","ATL","SFO"]
**Explanation:**
Another possible reconstruction is
["JFK","SFO","ATL","JFK","ATL","SFO"] but it is larger in lexical order.
**Constraints:**
* `1 <= tickets.length <= 300`
* `tickets[i].length == 2`
* fromi.length == 3
* toi.length == 3
* fromi
and toi
consist of uppercase English letters.
* fromi != toi