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Kotlin-based LeetCode algorithm problem solutions, regularly updated
397\. Integer Replacement
Medium
Given a positive integer `n`, you can apply one of the following operations:
1. If `n` is even, replace `n` with `n / 2`.
2. If `n` is odd, replace `n` with either `n + 1` or `n - 1`.
Return _the minimum number of operations needed for_ `n` _to become_ `1`.
**Example 1:**
**Input:** n = 8
**Output:** 3
**Explanation:** 8 -> 4 -> 2 -> 1
**Example 2:**
**Input:** n = 7
**Output:** 4
**Explanation:** 7 -> 8 -> 4 -> 2 -> 1 or 7 -> 6 -> 3 -> 2 -> 1
**Example 3:**
**Input:** n = 4
**Output:** 2
**Constraints:**
* 1 <= n <= 231 - 1