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Kotlin-based LeetCode algorithm problem solutions, regularly updated
466\. Count The Repetitions
Hard
We define `str = [s, n]` as the string `str` which consists of the string `s` concatenated `n` times.
* For example, `str == ["abc", 3] =="abcabcabc"`.
We define that string `s1` can be obtained from string `s2` if we can remove some characters from `s2` such that it becomes `s1`.
* For example, `s1 = "abc"` can be obtained from s2 = "ab**dbe**c"
based on our definition by removing the bolded underlined characters.
You are given two strings `s1` and `s2` and two integers `n1` and `n2`. You have the two strings `str1 = [s1, n1]` and `str2 = [s2, n2]`.
Return _the maximum integer_ `m` _such that_ `str = [str2, m]` _can be obtained from_ `str1`.
**Example 1:**
**Input:** s1 = "acb", n1 = 4, s2 = "ab", n2 = 2
**Output:** 2
**Example 2:**
**Input:** s1 = "acb", n1 = 1, s2 = "acb", n2 = 1
**Output:** 1
**Constraints:**
* `1 <= s1.length, s2.length <= 100`
* `s1` and `s2` consist of lowercase English letters.
* 1 <= n1, n2 <= 106