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CallSuperInConstructor

CallSuperInConstructor

It is a good practice to call super() in a constructor. If super() is not called but another constructor (such as an overloaded constructor) is called, this rule will not report it.

    
//ClassOrInterfaceDeclaration[ count (ExtendsList/*) > 0 ]
/ClassOrInterfaceBody
 /ClassOrInterfaceBodyDeclaration
 /ConstructorDeclaration[ count (.//ExplicitConstructorInvocation)=0 ]
    

Example(s):


public class Foo extends Bar{
  public Foo() {
   // call the constructor of Bar
   super();
  }
 public Foo(int code) {
  // do something with code
   this();
   // no problem with this
  }
}





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