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package edu.princeton.cs.algorithms;

import edu.princeton.cs.introcs.In;
import edu.princeton.cs.introcs.StdOut;

/*************************************************************************
 *  Compilation:  javac ThreeSum.java
 *  Execution:    java ThreeSum input.txt
 *  Dependencies: In.java StdOut.java Stopwatch.java
 *  Data files:   http://algs4.cs.princeton.edu/14analysis/1Kints.txt
 *                http://algs4.cs.princeton.edu/14analysis/2Kints.txt
 *                http://algs4.cs.princeton.edu/14analysis/4Kints.txt
 *                http://algs4.cs.princeton.edu/14analysis/8Kints.txt
 *                http://algs4.cs.princeton.edu/14analysis/16Kints.txt
 *                http://algs4.cs.princeton.edu/14analysis/32Kints.txt
 *                http://algs4.cs.princeton.edu/14analysis/1Mints.txt
 *
 *  A program with cubic running time. Read in N integers
 *  and counts the number of triples that sum to exactly 0
 *  (ignoring integer overflow).
 *
 *  % java ThreeSum 1Kints.txt 
 *  70
 *
 *  % java ThreeSum 2Kints.txt 
 *  528
 *
 *  % java ThreeSum 4Kints.txt 
 *  4039
 *
 *************************************************************************/

/**
 *  The ThreeSum class provides static methods for counting
 *  and printing the number of triples in an array of integers that sum to 0
 *  (ignoring integer overflow).
 *  

* This implementation uses a triply nested loop and takes proportional to N^3, * where N is the number of integers. *

* For additional documentation, see Section 1.4 of * Algorithms, 4th Edition by Robert Sedgewick and Kevin Wayne. * * @author Robert Sedgewick * @author Kevin Wayne */ public class ThreeSum { /** * Prints to standard output the (i, j, k) with i < j < k such that a[i] + a[j] + a[k] == 0. * @param a the array of integers */ public static void printAll(int[] a) { int N = a.length; for (int i = 0; i < N; i++) { for (int j = i+1; j < N; j++) { for (int k = j+1; k < N; k++) { if (a[i] + a[j] + a[k] == 0) { StdOut.println(a[i] + " " + a[j] + " " + a[k]); } } } } } /** * Returns the number of triples (i, j, k) with i < j < k such that a[i] + a[j] + a[k] == 0. * @param a the array of integers * @return the number of triples (i, j, k) with i < j < k such that a[i] + a[j] + a[k] == 0 */ public static int count(int[] a) { int N = a.length; int cnt = 0; for (int i = 0; i < N; i++) { for (int j = i+1; j < N; j++) { for (int k = j+1; k < N; k++) { if (a[i] + a[j] + a[k] == 0) { cnt++; } } } } return cnt; } /** * Reads in a sequence of integers from a file, specified as a command-line argument; * counts the number of triples sum to exactly zero; prints out the time to perform * the computation. */ public static void main(String[] args) { In in = new In(args[0]); int[] a = in.readAllInts(); Stopwatch timer = new Stopwatch(); int cnt = count(a); StdOut.println("elapsed time = " + timer.elapsedTime()); StdOut.println(cnt); } }





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