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package org.apache.poi.ss.formula.functions;

import org.apache.poi.ss.formula.CacheAreaEval;
import org.apache.poi.ss.formula.eval.EvaluationException;
import org.apache.poi.ss.formula.eval.NumberEval;
import org.apache.poi.ss.formula.eval.ValueEval;

import java.util.Arrays;

/**
 * Implementation of Excel 'Analysis ToolPak' function FREQUENCY()
* Returns a frequency distribution as a vertical array

*

* Syntax
* FREQUENCY(data_array, bins_array)

*

* data_array Required. An array of or reference to a set of values for which you want to count frequencies. * If data_array contains no values, FREQUENCY returns an array of zeros.
* bins_array Required. An array of or reference to intervals into which you want to group the values in data_array. * If bins_array contains no values, FREQUENCY returns the number of elements in data_array.
* * @author Yegor Kozlov */ public class Frequency extends Fixed2ArgFunction { public static final Function instance = new Frequency(); private Frequency() { // enforce singleton } public ValueEval evaluate(int srcRowIndex, int srcColumnIndex, ValueEval arg0, ValueEval arg1) { MatrixFunction.MutableValueCollector collector = new MatrixFunction.MutableValueCollector(false, false); double[] values; double[] bins; try { values = collector.collectValues(arg0); bins = collector.collectValues(arg1); } catch (EvaluationException e) { return e.getErrorEval(); } // can bins be not sorted? //bins = Arrays.stream(bins).sorted().distinct().toArray(); int[] histogram = histogram(values, bins); NumberEval[] result = Arrays.stream(histogram).boxed().map(NumberEval::new).toArray(NumberEval[]::new); return new CacheAreaEval(srcRowIndex, srcColumnIndex, srcRowIndex + result.length - 1, srcColumnIndex, result); } static int findBin(double value, double[] bins) { int idx = Arrays.binarySearch(bins, value); return idx >= 0 ? idx + 1 : -idx; } static int[] histogram(double[] values, double[] bins) { int[] histogram = new int[bins.length + 1]; for (double val : values) { histogram[findBin(val, bins) - 1]++; } return histogram; } }





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