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Liferay Frontend JS Minifier
/*
* Copyright 2010 The Closure Compiler Authors.
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
package com.google.javascript.jscomp;
import static com.google.common.base.Preconditions.checkArgument;
import com.google.common.base.Function;
import com.google.javascript.jscomp.graph.LatticeElement;
import java.util.Iterator;
import java.util.List;
/**
* Defines a way join a list of LatticeElements.
*/
interface JoinOp extends Function, L> {
/**
* An implementation of {@code JoinOp} that makes it easy to join to
* lattice elements at a time.
*/
abstract static class BinaryJoinOp
implements JoinOp {
@Override
public L apply(List values) {
checkArgument(!values.isEmpty());
int size = values.size();
if (size == 1) {
return values.get(0);
} else if (size == 2) {
return apply(values.get(0), values.get(1));
} else if (size <= 16) {
// Do a Tree merge which request the least number of merges
int mid = computeMidPoint(size);
return apply(
apply(values.subList(0, mid)),
apply(values.subList(mid, size)));
} else {
// If the merge set is getting out of hand, avoid tree merges as it is
// more memory intense. Instead, stick with linear merges that requires
// more merges but less memory. This avoids GC trashing.
Iterator iter = values.iterator();
L result = iter.next(); // Never null, we have 16+ values.
while (iter.hasNext()) {
result = apply(result, iter.next());
}
return result;
}
}
/**
* Creates a new lattice that will be the join of two input lattices.
*
* @return The join of {@code latticeA} and {@code latticeB}.
*/
abstract L apply(L latticeA, L latticeB);
/**
* Finds the midpoint of a list. The function will favor two lists of
* even length instead of two lists of the same odd length. The list
* must be at least length two.
*
* @param size Size of the list.
*/
static int computeMidPoint(int size) {
int midpoint = size >>> 1;
if (size > 4) {
/* Any list longer than 4 should prefer an even split point
* over the true midpoint, so that [0,6] splits at 2, not 3. */
midpoint &= -2; // (0xfffffffe) clears low bit so midpoint is even
}
return midpoint;
}
}
}