com.tangosol.util.AbstractLongArray Maven / Gradle / Ivy
Show all versions of coherence Show documentation
/*
* Copyright (c) 2000, 2020, Oracle and/or its affiliates.
*
* Licensed under the Universal Permissive License v 1.0 as shown at
* http://oss.oracle.com/licenses/upl.
*/
package com.tangosol.util;
import com.oracle.coherence.common.base.NaturalHasher;
/**
* An implementation of portions of the LongArray interface.
*
* @author cp
* @version 1.00 2002.04.24
*/
public abstract class AbstractLongArray
implements LongArray
{
/**
* Return the value stored at the specified index.
*
* @param lIndex a long index value
*
* @return the object stored at the specified index, or null
*/
public V get(long lIndex)
{
Iterator iter = iterator(lIndex);
if (iter.hasNext())
{
V value = iter.next();
return iter.getIndex() == lIndex ? value : null;
}
else
{
return null;
}
}
/**
* Add the passed element value to the LongArray and return the index at
* which the element value was stored.
*
* @param oValue the object to add to the LongArray
*
* @return the long index value at which the element value was stored
*/
public long add(V oValue)
{
long lIndex = getLastIndex() + 1L;
set(lIndex, oValue);
return lIndex;
}
/**
* Determine if the specified index is in use.
*
* @param lIndex a long index value
*
* @return true if a value (including null) is stored at the specified
* index, otherwise false
*/
public boolean exists(long lIndex)
{
Iterator iter = iterator(lIndex);
if (iter.hasNext())
{
iter.next();
return iter.getIndex() == lIndex;
}
else
{
return false;
}
}
/**
* Remove the specified key from the LongArray, returning its associated
* value.
*
* @param lIndex the index of the key to look for in the LongArray
*
* @return the associated value (which can be null) or null if the key is
* not in the LongArray
*/
public V remove(long lIndex)
{
Iterator iter = iterator(lIndex);
if (iter.hasNext())
{
V value = iter.next();
if (iter.getIndex() == lIndex)
{
iter.remove();
return value;
}
}
return null;
}
/**
* Remove all nodes in the specified range.
*
* @param lIndexFrom the floor index
* @param lIndexTo the ceiling index (exclusive)
*/
public void remove(long lIndexFrom, long lIndexTo)
{
for (Iterator iter = iterator(lIndexFrom); iter.hasNext(); )
{
iter.next();
if (iter.getIndex() < lIndexTo)
{
iter.remove();
}
else
{
break;
}
}
}
/**
* Determine if the LongArray contains the specified element.
*
* More formally, returns true
if and only if this LongArray
* contains at least one element e
such that
* (o==null ? e==null : o.equals(e))
.
*
* @param value element whose presence in this list is to be tested
*
* @return true
if this list contains the specified element
*/
public boolean contains(V value)
{
Iterator iter = iterator();
while (iter.hasNext())
{
if (NaturalHasher.INSTANCE.equals(value, iter.next()))
{
return true;
}
}
return false;
}
/**
* Remove all nodes from the LongArray.
*/
public void clear()
{
Iterator iter = iterator();
while (iter.hasNext())
{
iter.next();
iter.remove();
}
}
/**
* Test for empty LongArray.
*
* @return true if LongArray has no nodes
*/
public boolean isEmpty()
{
return getSize() == 0;
}
/**
* Determine the size of the LongArray.
*
* @return the number of nodes in the LongArray
*/
public int getSize()
{
int cItems = 0;
Iterator iter = iterator();
while (iter.hasNext())
{
iter.next();
++cItems;
}
return cItems;
}
/**
* Determine the first index that exists in the LongArray.
*
* @return the lowest long value that exists in this LongArray,
* or NOT_FOUND if the LongArray is empty
*/
public long getFirstIndex()
{
Iterator iter = iterator();
if (iter.hasNext())
{
iter.next();
return iter.getIndex();
}
else
{
return NOT_FOUND;
}
}
/**
* Determine the last index that exists in the LongArray.
*
* @return the highest long value that exists in this LongArray,
* or NOT_FOUND if the LongArray is empty
*/
public long getLastIndex()
{
Iterator iter = reverseIterator();
if (iter.hasNext())
{
iter.next();
return iter.getIndex();
}
else
{
return NOT_FOUND;
}
}
/**
* Return the index in this LongArray of the first occurrence of
* the specified element, or NOT_FOUND if this LongArray does not
* contain the specified element.
*/
public long indexOf(V oValue)
{
return indexOf(oValue, getFirstIndex());
}
/**
* Return the index in this LongArray of the first occurrence of
* the specified element such that (index is greater or equal to lIndex)
, or
* NOT_FOUND if this LongArray does not contain the specified
* element.
*/
public long indexOf(V oValue, long lIndex)
{
Iterator iter = iterator(lIndex);
while(iter.hasNext())
{
if (NaturalHasher.INSTANCE.equals(oValue, iter.next()))
{
return iter.getIndex();
}
}
return NOT_FOUND;
}
/**
* Return the index in this LongArray of the last occurrence of the
* specified element, or NOT_FOUND if this LongArray does not
* contain the specified element.
*/
public long lastIndexOf(V oValue)
{
return lastIndexOf(oValue, getLastIndex());
}
/**
* Return the index in this LongArray of the last occurrence of the
* specified element such that (index less than or equal to lIndex)
, or
* NOT_FOUND if this LongArray does not contain the specified
* element.
*/
public long lastIndexOf(V oValue, long lIndex)
{
Iterator iter = reverseIterator(lIndex);
while(iter.hasNext())
{
if (NaturalHasher.INSTANCE.equals(oValue, iter.next()))
{
return iter.getIndex();
}
}
return NOT_FOUND;
}
// ----- Object methods -------------------------------------------------
/**
* Provide a string representation of the LongArray.
*
* @return a human-readable String value describing the LongArray instance
*/
public String toString()
{
String sClass = getClass().getName();
sClass = sClass.substring(sClass.lastIndexOf('.') + 1);
StringBuffer sb = new StringBuffer();
sb.append(sClass)
.append('{');
boolean fFirst = true;
Iterator iter = iterator();
while (iter.hasNext())
{
if (fFirst)
{
fFirst = false;
}
else
{
sb.append(", ");
}
Object o = iter.next();
sb.append('[')
.append(iter.getIndex())
.append("]=")
.append(o);
}
sb.append('}');
return sb.toString();
}
/**
* Test for LongArray equality.
*
* @param o an Object to compare to this LongArray for equality
*
* @return true if the passed Object is a LongArray containing the same
* indexes and whose elements at those indexes are equal
*/
public boolean equals(Object o)
{
if (o instanceof LongArray)
{
LongArray that = (LongArray) o;
if (this.getSize() == that.getSize())
{
// short-cut: both are empty?
if (this.isEmpty())
{
return true;
}
// perform an in-order traversal, comparing each element
Iterator iterThis = this.iterator();
Iterator iterThat = that.iterator();
while (iterThis.hasNext() && iterThat.hasNext())
{
if (!NaturalHasher.INSTANCE.equals(iterThis.next(), iterThat.next())
|| iterThis.getIndex() != iterThat.getIndex())
{
return false;
}
}
return iterThis.hasNext() == iterThat.hasNext();
}
}
return false;
}
/**
* {@inheritDoc}
*/
public int hashCode()
{
int nHash = 0;
for (Iterator iter = this.iterator(); iter.hasNext(); )
{
nHash += NaturalHasher.INSTANCE.hashCode(iter.next());
}
return nHash;
}
// ----- cloneable interface --------------------------------------------
/**
* Make a clone of the LongArray. The element values are not deep-cloned.
*
* @return a clone of this LongArray object
*/
public AbstractLongArray clone()
{
try
{
return (AbstractLongArray) super.clone();
}
catch (CloneNotSupportedException e)
{
throw new RuntimeException(e);
}
}
}