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SPL(Structured Process Language) A programming language specially for structured data computing.
package com.scudata.expression.fn.algebra;
import com.scudata.common.MessageManager;
import com.scudata.common.RQException;
import com.scudata.dm.Context;
import com.scudata.dm.Sequence;
import com.scudata.expression.Function;
import com.scudata.expression.IParam;
import com.scudata.resources.EngineMessage;
/**
* ????˹Ƥ????ϵ??spearman(A,B)??Bʡ??ʱ??to(A.len())
* @author bd, 2021.1.19
*
*/
public class Spearman extends Function {
/**
* ??????ʽ????Ч?ԣ???Ч???׳??쳣
*/
public void checkValidity() {
if (param == null) {
MessageManager mm = EngineMessage.get();
throw new RQException("spearman" + mm.getMessage("function.missingParam"));
}
}
public Object calculate(Context ctx) {
Object o1 = null, o2 = null;
if (param.isLeaf()) {
o1 = param.getLeafExpression().calculate(ctx);
if (o1 instanceof Sequence) {
} else {
MessageManager mm = EngineMessage.get();
throw new RQException("spearman" + mm.getMessage("function.paramTypeError"));
}
} else {
if (param.getSubSize() != 2) {
MessageManager mm = EngineMessage.get();
throw new RQException("spearman" + mm.getMessage("function.invalidParam"));
}
IParam sub1 = param.getSub(0);
IParam sub2 = param.getSub(1);
if (sub1 == null) {
MessageManager mm = EngineMessage.get();
throw new RQException("spearman" + mm.getMessage("function.invalidParam"));
}
o1 = sub1.getLeafExpression().calculate(ctx);
o2 = sub2 == null ? null : sub2.getLeafExpression().calculate(ctx);
}
if (o2 == null) {
int len = o1 instanceof Sequence ? ((Sequence) o1).length() : 1;
o2 = new Sequence(1, len);
}
if (o1 instanceof Sequence && o2 instanceof Sequence) {
return Double.valueOf(spearman((Sequence)o1, (Sequence)o2));
} else {
MessageManager mm = EngineMessage.get();
throw new RQException("spearman" + mm.getMessage("function.paramTypeError"));
}
}
public static double spearman(Sequence x, Sequence y) {
double n = (double) x.length();
Sequence p = x.ranks("s");
Sequence q = y.ranks("s");
Sequence d = p.memberSubtract(q);
double sumup = 0;
for (int i = 1; i <= n; i++) {
double dcur = ((Number) d.get(i)).doubleValue();
sumup += dcur * dcur;
}
return 1-6*sumup/n/(n*n-1);
}
}
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