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/*
* Licensed to the Apache Software Foundation (ASF) under one or more
* contributor license agreements. See the NOTICE file distributed with
* this work for additional information regarding copyright ownership.
* The ASF licenses this file to You under the Apache License, Version 2.0
* (the "License"); you may not use this file except in compliance with
* the License. You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
package org.apache.commons.codec.language;
/**
* Encodes a string into a Caverphone 2.0 value.
*
* This is an algorithm created by the Caversham Project at the University of Otago. It implements the Caverphone 2.0
* algorithm:
*
* @see Wikipedia - Caverphone
* @see Caverphone 2.0 specification
* @since 1.5
*
* This class is immutable and thread-safe.
*/
public class Caverphone2 extends AbstractCaverphone {
private static final String TEN_1 = "1111111111";
/**
* Encodes the given String into a Caverphone 2.0 value.
*
* @param source
* String the source string
* @return A caverphone code for the given String
*/
@Override
public String encode(final String source) {
String txt = source;
if (txt == null || txt.length() == 0) {
return TEN_1;
}
// 1. Convert to lowercase
txt = txt.toLowerCase(java.util.Locale.ENGLISH);
// 2. Remove anything not A-Z
txt = txt.replaceAll("[^a-z]", "");
// 2.5. Remove final e
txt = txt.replaceAll("e$", ""); // 2.0 only
// 3. Handle various start options
txt = txt.replaceAll("^cough", "cou2f");
txt = txt.replaceAll("^rough", "rou2f");
txt = txt.replaceAll("^tough", "tou2f");
txt = txt.replaceAll("^enough", "enou2f"); // 2.0 only
txt = txt.replaceAll("^trough", "trou2f"); // 2.0 only
// note the spec says ^enough here again, c+p error I assume
txt = txt.replaceAll("^gn", "2n");
// End
txt = txt.replaceAll("mb$", "m2");
// 4. Handle replacements
txt = txt.replaceAll("cq", "2q");
txt = txt.replaceAll("ci", "si");
txt = txt.replaceAll("ce", "se");
txt = txt.replaceAll("cy", "sy");
txt = txt.replaceAll("tch", "2ch");
txt = txt.replaceAll("c", "k");
txt = txt.replaceAll("q", "k");
txt = txt.replaceAll("x", "k");
txt = txt.replaceAll("v", "f");
txt = txt.replaceAll("dg", "2g");
txt = txt.replaceAll("tio", "sio");
txt = txt.replaceAll("tia", "sia");
txt = txt.replaceAll("d", "t");
txt = txt.replaceAll("ph", "fh");
txt = txt.replaceAll("b", "p");
txt = txt.replaceAll("sh", "s2");
txt = txt.replaceAll("z", "s");
txt = txt.replaceAll("^[aeiou]", "A");
txt = txt.replaceAll("[aeiou]", "3");
txt = txt.replaceAll("j", "y"); // 2.0 only
txt = txt.replaceAll("^y3", "Y3"); // 2.0 only
txt = txt.replaceAll("^y", "A"); // 2.0 only
txt = txt.replaceAll("y", "3"); // 2.0 only
txt = txt.replaceAll("3gh3", "3kh3");
txt = txt.replaceAll("gh", "22");
txt = txt.replaceAll("g", "k");
txt = txt.replaceAll("s+", "S");
txt = txt.replaceAll("t+", "T");
txt = txt.replaceAll("p+", "P");
txt = txt.replaceAll("k+", "K");
txt = txt.replaceAll("f+", "F");
txt = txt.replaceAll("m+", "M");
txt = txt.replaceAll("n+", "N");
txt = txt.replaceAll("w3", "W3");
txt = txt.replaceAll("wh3", "Wh3");
txt = txt.replaceAll("w$", "3"); // 2.0 only
txt = txt.replaceAll("w", "2");
txt = txt.replaceAll("^h", "A");
txt = txt.replaceAll("h", "2");
txt = txt.replaceAll("r3", "R3");
txt = txt.replaceAll("r$", "3"); // 2.0 only
txt = txt.replaceAll("r", "2");
txt = txt.replaceAll("l3", "L3");
txt = txt.replaceAll("l$", "3"); // 2.0 only
txt = txt.replaceAll("l", "2");
// 5. Handle removals
txt = txt.replaceAll("2", "");
txt = txt.replaceAll("3$", "A"); // 2.0 only
txt = txt.replaceAll("3", "");
// 6. put ten 1s on the end
txt = txt + TEN_1;
// 7. take the first ten characters as the code
return txt.substring(0, TEN_1.length());
}
}