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com.yahoo.sketches.quantiles.ItemsPmfCdfImpl Maven / Gradle / Ivy

/*
 * Copyright 2017, Yahoo! Inc. Licensed under the terms of the
 * Apache License 2.0. See LICENSE file at the project root for terms.
 */

package com.yahoo.sketches.quantiles;

import java.util.Arrays;
import java.util.Comparator;

class ItemsPmfCdfImpl {

  static  double[] getPMFOrCDF(final ItemsSketch sketch, final T[] splitPoints,
      final boolean isCDF) {
    final long[] counters = internalBuildHistogram(splitPoints, sketch);
    final int numCounters = counters.length;
    final double[] result = new double[numCounters];
    final double n = sketch.getN();
    long subtotal = 0;
    if (isCDF) {
      for (int j = 0; j < numCounters; j++) {
        final long count = counters[j];
        subtotal += count;
        result[j] = subtotal / n; //normalize by n
      }
    } else { // PMF
      for (int j = 0; j < numCounters; j++) {
        final long count = counters[j];
        subtotal += count;
        result[j] = count / n; //normalize by n
      }
    }
    assert subtotal == n; //internal consistency check
    return result;
  }

  /**
   * Shared algorithm for both PMF and CDF functions. The splitPoints must be unique, monotonically
   * increasing values.
   * @param splitPoints an array of m unique, monotonically increasing values
   * that divide the ordered domain into m+1 consecutive disjoint intervals.
   * @param sketch the given quantiles sketch
   * @return the unnormalized, accumulated counts of m + 1 intervals.
   */
  @SuppressWarnings("unchecked")
  private static  long[] internalBuildHistogram(final T[] splitPoints, final ItemsSketch sketch) {
    final Object[] levelsArr  = sketch.getCombinedBuffer();
    final Object[] baseBuffer = levelsArr;
    final int bbCount = sketch.getBaseBufferCount();
    ItemsUtil.validateValues(splitPoints, sketch.getComparator());

    final int numSplitPoints = splitPoints.length;
    final int numCounters = numSplitPoints + 1;
    final long[] counters = new long[numCounters];

    long weight = 1;
    if (numSplitPoints < 50) { // empirically determined crossover
      // sort not worth it when few split points
      ItemsPmfCdfImpl.bilinearTimeIncrementHistogramCounters(
          (T[]) baseBuffer, 0, bbCount, weight, splitPoints, counters, sketch.getComparator());
    } else {
      Arrays.sort(baseBuffer, 0, bbCount);
      // sort is worth it when many split points
      linearTimeIncrementHistogramCounters(
          (T[]) baseBuffer, 0, bbCount, weight, splitPoints, counters, sketch.getComparator()
      );
    }

    long myBitPattern = sketch.getBitPattern();
    final int k = sketch.getK();
    assert myBitPattern == sketch.getN() / (2L * k); // internal consistency check
    for (int lvl = 0; myBitPattern != 0L; lvl++, myBitPattern >>>= 1) {
      weight += weight; // *= 2
      if ((myBitPattern & 1L) > 0L) { //valid level exists
        // the levels are already sorted so we can use the fast version
        linearTimeIncrementHistogramCounters(
            (T[]) levelsArr, (2 + lvl) * k, k, weight, splitPoints, counters, sketch.getComparator());
      }
    }
    return counters;
  }

  /**
   * Because of the nested loop, cost is O(numSamples * numSplitPoints), which is bilinear.
   * This method does NOT require the samples to be sorted.
   * @param samples array of samples
   * @param offset into samples array
   * @param numSamples number of samples in samples array
   * @param weight of the samples
   * @param splitPoints must be unique and sorted. Number of splitPoints + 1 == counters.length.
   * @param counters array of counters
   */
  private static  void bilinearTimeIncrementHistogramCounters(final T[] samples, final int offset,
      final int numSamples, final long weight, final T[] splitPoints, final long[] counters,
      final Comparator comparator) {
    assert (splitPoints.length + 1 == counters.length);
    for (int i = 0; i < numSamples; i++) {
      final T sample = samples[i + offset];
      int j = 0;
      for (j = 0; j < splitPoints.length; j++) {
        final T splitpoint = splitPoints[j];
        if (comparator.compare(sample, splitpoint) < 0) {
          break;
        }
      }
      assert j < counters.length;
      counters[j] += weight;
    }
  }

  /**
   * This one does a linear time simultaneous walk of the samples and splitPoints. Because this
   * internal procedure is called multiple times, we require the caller to ensure these 3 properties:
   * 
    *
  1. samples array must be sorted.
  2. *
  3. splitPoints must be unique and sorted
  4. *
  5. number of SplitPoints + 1 == counters.length
  6. *
* @param samples sorted array of samples * @param offset into samples array * @param numSamples number of samples in samples array * @param weight of the samples * @param splitPoints must be unique and sorted. Number of splitPoints + 1 = counters.length. * @param counters array of counters */ private static void linearTimeIncrementHistogramCounters(final T[] samples, final int offset, final int numSamples, final long weight, final T[] splitPoints, final long[] counters, final Comparator comparator) { int i = 0; int j = 0; while (i < numSamples && j < splitPoints.length) { if (comparator.compare(samples[i + offset], splitPoints[j]) < 0) { counters[j] += weight; // this sample goes into this bucket i++; // move on to next sample and see whether it also goes into this bucket } else { j++; // no more samples for this bucket. move on the next bucket. } } // now either i == numSamples(we are out of samples), or // j == numSplitPoints(out of buckets, but there are more samples remaining) // we only need to do something in the latter case. if (j == splitPoints.length) { counters[j] += (weight * (numSamples - i)); } } }




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