com.yahoo.sketches.quantiles.ItemsPmfCdfImpl Maven / Gradle / Ivy
/*
* Copyright 2017, Yahoo! Inc. Licensed under the terms of the
* Apache License 2.0. See LICENSE file at the project root for terms.
*/
package com.yahoo.sketches.quantiles;
import java.util.Arrays;
import java.util.Comparator;
class ItemsPmfCdfImpl {
static double[] getPMFOrCDF(final ItemsSketch sketch, final T[] splitPoints,
final boolean isCDF) {
final long[] counters = internalBuildHistogram(splitPoints, sketch);
final int numCounters = counters.length;
final double[] result = new double[numCounters];
final double n = sketch.getN();
long subtotal = 0;
if (isCDF) {
for (int j = 0; j < numCounters; j++) {
final long count = counters[j];
subtotal += count;
result[j] = subtotal / n; //normalize by n
}
} else { // PMF
for (int j = 0; j < numCounters; j++) {
final long count = counters[j];
subtotal += count;
result[j] = count / n; //normalize by n
}
}
assert subtotal == n; //internal consistency check
return result;
}
/**
* Shared algorithm for both PMF and CDF functions. The splitPoints must be unique, monotonically
* increasing values.
* @param splitPoints an array of m unique, monotonically increasing values
* that divide the ordered domain into m+1 consecutive disjoint intervals.
* @param sketch the given quantiles sketch
* @return the unnormalized, accumulated counts of m + 1 intervals.
*/
@SuppressWarnings("unchecked")
private static long[] internalBuildHistogram(final T[] splitPoints, final ItemsSketch sketch) {
final Object[] levelsArr = sketch.getCombinedBuffer();
final Object[] baseBuffer = levelsArr;
final int bbCount = sketch.getBaseBufferCount();
ItemsUtil.validateValues(splitPoints, sketch.getComparator());
final int numSplitPoints = splitPoints.length;
final int numCounters = numSplitPoints + 1;
final long[] counters = new long[numCounters];
long weight = 1;
if (numSplitPoints < 50) { // empirically determined crossover
// sort not worth it when few split points
ItemsPmfCdfImpl.bilinearTimeIncrementHistogramCounters(
(T[]) baseBuffer, 0, bbCount, weight, splitPoints, counters, sketch.getComparator());
} else {
Arrays.sort(baseBuffer, 0, bbCount);
// sort is worth it when many split points
linearTimeIncrementHistogramCounters(
(T[]) baseBuffer, 0, bbCount, weight, splitPoints, counters, sketch.getComparator()
);
}
long myBitPattern = sketch.getBitPattern();
final int k = sketch.getK();
assert myBitPattern == sketch.getN() / (2L * k); // internal consistency check
for (int lvl = 0; myBitPattern != 0L; lvl++, myBitPattern >>>= 1) {
weight += weight; // *= 2
if ((myBitPattern & 1L) > 0L) { //valid level exists
// the levels are already sorted so we can use the fast version
linearTimeIncrementHistogramCounters(
(T[]) levelsArr, (2 + lvl) * k, k, weight, splitPoints, counters, sketch.getComparator());
}
}
return counters;
}
/**
* Because of the nested loop, cost is O(numSamples * numSplitPoints), which is bilinear.
* This method does NOT require the samples to be sorted.
* @param samples array of samples
* @param offset into samples array
* @param numSamples number of samples in samples array
* @param weight of the samples
* @param splitPoints must be unique and sorted. Number of splitPoints + 1 == counters.length.
* @param counters array of counters
*/
private static void bilinearTimeIncrementHistogramCounters(final T[] samples, final int offset,
final int numSamples, final long weight, final T[] splitPoints, final long[] counters,
final Comparator super T> comparator) {
assert (splitPoints.length + 1 == counters.length);
for (int i = 0; i < numSamples; i++) {
final T sample = samples[i + offset];
int j = 0;
for (j = 0; j < splitPoints.length; j++) {
final T splitpoint = splitPoints[j];
if (comparator.compare(sample, splitpoint) < 0) {
break;
}
}
assert j < counters.length;
counters[j] += weight;
}
}
/**
* This one does a linear time simultaneous walk of the samples and splitPoints. Because this
* internal procedure is called multiple times, we require the caller to ensure these 3 properties:
*
* - samples array must be sorted.
* - splitPoints must be unique and sorted
* - number of SplitPoints + 1 == counters.length
*
* @param samples sorted array of samples
* @param offset into samples array
* @param numSamples number of samples in samples array
* @param weight of the samples
* @param splitPoints must be unique and sorted. Number of splitPoints + 1 = counters.length.
* @param counters array of counters
*/
private static void linearTimeIncrementHistogramCounters(final T[] samples, final int offset,
final int numSamples, final long weight, final T[] splitPoints, final long[] counters,
final Comparator super T> comparator) {
int i = 0;
int j = 0;
while (i < numSamples && j < splitPoints.length) {
if (comparator.compare(samples[i + offset], splitPoints[j]) < 0) {
counters[j] += weight; // this sample goes into this bucket
i++; // move on to next sample and see whether it also goes into this bucket
} else {
j++; // no more samples for this bucket. move on the next bucket.
}
}
// now either i == numSamples(we are out of samples), or
// j == numSplitPoints(out of buckets, but there are more samples remaining)
// we only need to do something in the latter case.
if (j == splitPoints.length) {
counters[j] += (weight * (numSamples - i));
}
}
}
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