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rules.jshint.E029.html Maven / Gradle / Ivy

    
When do I get this error?
The "Unclosed string" error is thrown when JSLint or JSHint encounters a a
string that is not closed before the next line break or the end of the
program. There are numerous situations that could cause this. In this first
example, we accidentally forget to close our string:
​x
 
1
var myString = "my string,
2
    myNumber = 10;
3
​
JSLint found 1 error
Which linter should be used for this code snippet:
 JSLint JSHint ESLint
Which version of the linter should be used:
Update
Version 2015-09-23
Line 0:
Unclosed string.

In the next example, we want our string to include a backslash character. The
string appears to be closed but actually isn't, due to the backslash character
escaping the closing quote:
3
 
1
var myString = "my string\",
2
    myNumber = 10;
3
​
JSLint found 1 error
Which linter should be used for this code snippet:
 JSLint JSHint ESLint
Which version of the linter should be used:
Update
Version 2015-09-23
Line 0:
Unclosed string.

And this final example, which makes use of the multiline strings allowed by
ECMAScript 5, features a string that has not closed by the end of the program
(the previous two examples failed at the first line break):
3
 
1
var myString = "my multiline \
2
                string
3
​
JSLint found 1 error
Which linter should be used for this code snippet:
 JSLint JSHint ESLint
Which version of the linter should be used:
Update
Version 2015-09-23
Line 0:
Unclosed string.

Why do I get this error?
This error is raised to highlight a fatal JavaScript syntax error. Your code
will not run unless you fix this issue. The ECMAScript grammar states that any
string literal must be closed by the same character (either " or ') that
opened it (ES5 §7.8.4):

StringLiteral ::

    " DoubleStringCharactersopt "

    ' SingleStringCharactersopt '

To fix the error, simply close any unclosed strings:
3
 
1
var myString = "my string",
2
    myNumber = 10;
3
​
JSLint found no errors
Which linter should be used for this code snippet:
 JSLint JSHint ESLint
Which version of the linter should be used:
Update
Version 2015-09-23

The second example above failed because the backslash character was escaping the
closing quote, turning it into a literal character rather than a syntactic
structure. To include a backslash in a string, you need to escape the backslash
itself:
3
 
1
var myString = "my string\\",
2
    myNumber = 10;
3
​
JSLint found no errors
Which linter should be used for this code snippet:
 JSLint JSHint ESLint
Which version of the linter should be used:
Update
Version 2015-09-23

In JSHint 1.0.0 and above you have the ability to ignore any warning with a
special option syntax. Since this message relates to a fatal
syntax error you cannot disable it.