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com.kaka.util.StringUtils Maven / Gradle / Ivy
package com.kaka.util;
import java.nio.charset.StandardCharsets;
import java.security.MessageDigest;
import java.util.ArrayList;
import java.util.Collection;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
/**
* 字符串辅助工具集
*
* @author zkpursuit
*/
public class StringUtils {
private static final char[] nameChars = {'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z', 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', '1', '2', '3', '4', '5', '6', '7', '8', '9', '0'};
/**
* 随机生成字符串
*
* @param chars 字符数组
* @param count 字符串字符个数
* @param charRepeat 是否允许字符串中有重复字符,true为可以有重复字符
* @return 随机的字符串
*/
public static String randomString(char[] chars, int count, boolean charRepeat) {
StringBuilder sb = new StringBuilder();
int len = chars.length - 1;
int index;
char c;
int ci = 0;
while (ci < count) {
if (!charRepeat) {
do {
c = chars[MathUtils.getRandom().nextInt(len)];
int length = sb.length();
index = -1;
for (int i = 0; i < length; i++) {
char _c = sb.charAt(i);
if (_c == c) {
index = i;
break;
}
}
} while (index >= 0);
} else {
c = chars[MathUtils.getRandom().nextInt(len)];
}
sb.append(c);
ci++;
}
return sb.toString();
}
/**
* 随机生成字符串
*
* @param count 字符串字符个数
* @param charRepeat 是否允许字符串中有重复字符,true为可以有重复字符
* @return 包含(A-Z)或(a-z)或(0-9)的字符串
*/
public static String randomString(int count, boolean charRepeat) {
return randomString(nameChars, count, charRepeat);
}
/**
* 字符串替换
*
* @param s 源字符串
* @param sub 被替换的字符
* @param with 替换的字符
* @return 替换后的新字符串
*/
public static String replaceSub(String s, String sub, String with) {
int c = 0;
int i = s.indexOf(sub, c);
if (i == -1) {
return s;
}
StringBuilder buf = new StringBuilder(s.length() + with.length());
do {
buf.append(s, c, i);
buf.append(with);
c = i + sub.length();
} while ((i = s.indexOf(sub, c)) != -1);
if (c < s.length()) {
buf.append(s.substring(c));
}
return buf.toString();
}
/**
* 将src字符串中的regex字符串依次替换为args中的值
*
* @param src 源字符串
* @param regex 需替换的正则表达式
* @param args 被替换的字符串
* @return 替换后的字符串
*/
public static String replaceByRegex(String src, String regex, Object... args) {
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(src);
StringBuffer sb = new StringBuffer();
for (Object arg : args) {
if (!matcher.find()) {
break;
}
matcher.appendReplacement(sb, String.valueOf(arg));
}
matcher.appendTail(sb);
return sb.toString();
}
/**
* 格式化字符串
* 将src字符串中的{}字符串依次替换为args中的值
*
* @param src 源字符串
* @param args 替换的新值列表
* @return 新的字符串
*/
public static String format(String src, Object... args) {
return replaceByRegex(src, "\\{[ 0-9]*\\}", args);
}
/**
* 将number数字转为为count位的字符串,不足count位,前面补0
*
* @param number 正整数
* @param count 位数
* @return count位字符串
*/
public static String repairZeroToFirst(int number, int count) {
return String.format("%0" + count + "d", number);
}
/**
* 将number数字转为为count位的字符串,不足count位,后面补0
*
* @param number 正整数
* @param count 位数
* @return count位字符串
*/
public static String repairZeroToLast(int number, int count) {
return String.format("%1$0" + count + "d", number);
}
private static void getNextVal(char[] p, int[] next) {
int pLen = p.length;
next[0] = -1;
int k = -1;
int j = 0;
while (j < pLen - 1) {
//p[k]表示前缀,p[j]表示后缀
if (k == -1 || p[j] == p[k]) {
++j;
++k;
//较之前next数组求法,改动在下面4行
if (p[j] != p[k])
next[j] = k; //之前只有这一行
else
//因为不能出现p[j] = p[ next[j ]],所以当出现时需要继续递归,k = next[k] = next[next[k]]
next[j] = next[k];
} else {
k = next[k];
}
}
}
/**
* kmp字符串查找算法
* 参考博文:...
* 经jdk8上测试简单英文字符串匹配搜索100000+次,性能不及String原生indexOf算法
*
* @param src 源字符串
* @param pstr 搜索的字符串
* @return 字符串索引
*/
public static int indexOfByKmp(String src, String pstr) {
int i = 0;
int j = 0;
int sLen = src.length();
int pLen = pstr.length();
char[] s = src.toCharArray();
char[] p = pstr.toCharArray();
int[] next = new int[pLen];
getNextVal(p, next);
while (i < sLen && j < pLen) {
//①如果j = -1,或者当前字符匹配成功(即S[i] == P[j]),都令i++,j++
if (j == -1 || s[i] == p[j]) {
i++;
j++;
} else {
//②如果j != -1,且当前字符匹配失败(即S[i] != P[j]),则令 i 不变,j = next[j]
//next[j]即为j所对应的next值
j = next[j];
}
}
if (j == pLen) {
return i - j;
}
return -1;
}
/**
* 获取src中匹配regex正则规则的字符串集合
*
* @param src 源字符串
* @param regex 正则表达式
* @param regexMatchIndex 0表示匹配整个表达式,其它正数表示正则表达式中的括号中所标示的子表达式
* @return 字符串集合
*/
public static List match(String src, String regex, int regexMatchIndex) {
if (src == null) {
return null;
}
if (regex == null) {
return null;
}
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(src);
List result = null;
while (matcher.find()) {
if (result == null) {
result = new ArrayList<>();
}
result.add(matcher.group(regexMatchIndex));
}
return result;
}
/**
* 获取src中匹配regex正则规则的字符串集合
*
* @param src 源字符串
* @param regex 正则表达式
* @return 字符串集合
*/
public static List match(String src, String regex) {
return match(src, regex, 0);
}
/**
* 获取src中匹配{数字}正则规则的字符串集合
*
* @param src 源字符串
* @return 新的字符串
*/
public static List match(String src) {
return match(src, "\\{[0-9&]*\\}");
}
/**
* 是否为数字的正则
*/
private final static Pattern intPattern = Pattern.compile("^(\\-|\\+)?[0-9]*$");
/**
* 判断字符串是否为纯整型数字
*
* @param src 待判断的字符串
* @return true为纯整型数字
*/
public static boolean isInteger(String src) {
if (src == null) {
return false;
}
if (src.isEmpty()) {
return false;
}
return intPattern.matcher(src).matches();
}
/**
* 是否为数字的正则
*/
private final static Pattern numberPattern = Pattern.compile("^(\\-|\\+)?[0-9]*(\\.[0-9]*)?$");
/**
* 判断字符串是否为数字
*
* @param src 待判断的字符串
* @return true为数字
*/
public static boolean isNumeric(String src) {
if (src == null) {
return false;
}
if (src.isEmpty()) {
return false;
}
return numberPattern.matcher(src).matches();
}
/**
* 判断字符串是否不为null或者""
*
* @param src 源字符串
* @return true不为null或者"",false为null或者""
*/
public static boolean isNotEmpty(String src) {
if (src == null) {
return false;
}
return !src.isEmpty();
}
public static final char[] DIGITS_LOWER = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f'};
public static final char[] DIGITS_UPPER = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
/**
* 将字符转换为16进制的数字
*
* @param ch 字符
* @param index 字符数组中的索引位置
* @return 16进制数字
*/
private static int toDigit(final char ch, final int index) {
final int digit = Character.digit(ch, 16);
if (digit == -1) {
throw new IllegalArgumentException("Illegal hexadecimal character " + ch + " at index " + index);
}
return digit;
}
private static final char[] hex_digits_numbers = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
/**
* 任意字符串转数字
*
* @param src 字符串
* @return 转换后的数字
*/
public static long toNumber(final String src) {
byte[] source = src.getBytes(StandardCharsets.UTF_8);
String s = null;
try {
MessageDigest md = MessageDigest.getInstance("MD5");
md.update(source);
byte[] tmp = md.digest();
char[] str = new char[16];
int k = 0;
for (int i = 0; i < 16; i++) {
byte byte0 = tmp[i];
//只取高位
str[k++] = hex_digits_numbers[(byte0 >>> 4 & 0xf) % 10];
//str[k++] = hexDigits[byte0 & 0xf];
}
s = new String(str); // 换后的结果转换为字符串
} catch (Exception e) {
}
if (s == null) {
return 0;
}
return Long.parseLong(s);
}
/**
* 编码字节数组为16进制字符
*
* @param data 字节数组
* @param toDigits 基础编码数据
* @return 编码后的字符数组
*/
public static char[] encodeByteToHex(final byte[] data, final char[] toDigits) {
final int len = data.length;
final char[] out = new char[len << 1];
//两个字符构成十六进制值。
for (int i = 0, j = 0; i < len; i++) {
out[j++] = toDigits[(0xF0 & data[i]) >>> 4];
out[j++] = toDigits[0x0F & data[i]];
}
return out;
}
/**
* 编码字节数组为16进制字符
*
* @param data 字节数组
* @return 编码后的字符数组
*/
public static char[] encodeByteToHex(final byte[] data) {
return encodeByteToHex(data, DIGITS_UPPER);
}
/**
* 编码字节数组为16进制字符
*
* @param data 字节数组
* @return 编码后的字符串
*/
public static String encodeByteToHexString(final byte[] data) {
return new String(encodeByteToHex(data));
}
/**
* 将16进制字符编码为字节
*
* @param data 字符数组
* @return 字节数组
*/
public static byte[] decodeHexToByte(final char[] data) {
final int len = data.length;
if ((len & 0x01) != 0) {
throw new IllegalArgumentException("字符数组长度必然为偶数。");
}
final byte[] out = new byte[len >> 1];
for (int i = 0, j = 0; j < len; i++) {
int f = toDigit(data[j], j) << 4;
j++;
f = f | toDigit(data[j], j);
j++;
out[i] = (byte) (f & 0xFF);
}
return out;
}
/**
* 将16进制字符编码为字节
*
* @param data 字符串
* @return 字节数组
*/
public static byte[] decodeHexToByte(final String data) {
return decodeHexToByte(data.toCharArray());
}
/**
* 判断字符是否为中文字符
*
* @param c 字符
* @return 为中文字符返回true,否则为false
*/
public static boolean isChinese(char c) {
Character.UnicodeBlock ub = Character.UnicodeBlock.of(c);
return ub == Character.UnicodeBlock.CJK_UNIFIED_IDEOGRAPHS
|| ub == Character.UnicodeBlock.CJK_COMPATIBILITY_IDEOGRAPHS
|| ub == Character.UnicodeBlock.CJK_UNIFIED_IDEOGRAPHS_EXTENSION_A
|| ub == Character.UnicodeBlock.GENERAL_PUNCTUATION
|| ub == Character.UnicodeBlock.CJK_SYMBOLS_AND_PUNCTUATION
|| ub == Character.UnicodeBlock.HALFWIDTH_AND_FULLWIDTH_FORMS;
}
/**
* 判断字符串中是否包含中文字符
*
* @param src 待判断的源字符串
* @return 包含中文字符返回true, 否则返回false
*/
public static boolean hasChinese(String src) {
char[] ch = src.toCharArray();
for (char c : ch) {
if (isChinese(c)) {
return true;
}
}
return false;
}
/**
* 组合列表元素为字符串
*
* @param list 数据列表
* @param open 开始字符串
* @param separator 分隔符
* @param close 关闭字符串
* @return 组合后的字符串
*/
public static String group(Collection> list, String open, String separator, String close) {
StringBuilder sb = new StringBuilder();
sb.append(open);
int size = list.size();
list.forEach((v) -> sb.append(v).append(separator));
if (size > 0) {
int len = sb.length();
sb.delete(len - separator.length(), len);
}
sb.append(close);
return sb.toString();
}
/**
* 组合数组元素为字符串
*
* @param array 待组合的数组
* @param open 开始字符串
* @param separator 分隔符
* @param close 关闭字符串
* @return 组合后的字符串
*/
public static String group(Object array, String open, String separator, String close) {
if (!array.getClass().isArray()) {
return null;
}
StringBuilder sb = new StringBuilder();
sb.append(open);
int size = ArrayUtils.getLength(array);
for (int i = 0; i < size; i++) {
if (i > 0) {
sb.append(separator);
}
sb.append(ArrayUtils.get(array, i));
}
sb.append(close);
return sb.toString();
}
/**
* 求解两字符串的最长公共子串
* 原理:二维矩阵中,将str1的每个字符置于行首,str2的每个字符置于列首,
* 再于矩阵中查询出连续行列值。
*
* @param str1 字符串
* @param str2 字符串
* @return 最长公共子串
*/
public static String getMaxSubstring(String str1, String str2) {
int row = 0;
int col = str2.length();
int end_index = 0;
int max_len = 0;
while (row < str1.length()) {
int i = row;
int j = col;
int pre = 0;
while (i < str1.length() && j < str2.length()) {
if (str1.charAt(i) == str2.charAt(j)) {
pre += 1;
if (pre > max_len) {
max_len = pre;
end_index = i;
}
} else {
pre = 0;
}
i++;
j++;
}
if (col > 0) {
col--;
} else {
row++;
}
}
//最长子串长度即为max_len
if (max_len > 0) {
int start = end_index - max_len + 1;
int end = end_index + 1;
return str1.substring(start, end);
}
return null;
}
public static void main(String[] args) {
System.out.println(getMaxSubstring("dsafjdsafdf3qewrdf", "rrqrewqfjdsafdf3qewjdlfaj"));
System.out.println(getMaxSubstring("ab", "b"));
}
}