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The ActiveMQ Message Broker implementation
/**
* Licensed to the Apache Software Foundation (ASF) under one or more
* contributor license agreements. See the NOTICE file distributed with
* this work for additional information regarding copyright ownership.
* The ASF licenses this file to You under the Apache License, Version 2.0
* (the "License"); you may not use this file except in compliance with
* the License. You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
package org.apache.activemq.broker.region.policy;
import java.util.Iterator;
import java.util.List;
import org.apache.activemq.broker.region.MessageReference;
import org.apache.activemq.broker.region.Subscription;
import org.apache.activemq.filter.MessageEvaluationContext;
/**
* Dispatch policy that causes every subscription to see messages in the same
* order.
*
* @org.apache.xbean.XBean
*
*/
public class StrictOrderDispatchPolicy implements DispatchPolicy {
/**
* @param node
* @param msgContext
* @param consumers
* @return true if dispatched
* @throws Exception
* @see org.apache.activemq.broker.region.policy.DispatchPolicy#dispatch(org.apache.activemq.broker.region.MessageReference,
* org.apache.activemq.filter.MessageEvaluationContext, java.util.List)
*/
public boolean dispatch(MessageReference node, MessageEvaluationContext msgContext, List consumers) throws Exception {
// Big synch here so that only 1 message gets dispatched at a time.
// Ensures
// Everyone sees the same order.
synchronized (consumers) {
int count = 0;
for (Iterator iter = consumers.iterator(); iter.hasNext();) {
Subscription sub = (Subscription)iter.next();
// Only dispatch to interested subscriptions
if (!sub.matches(node, msgContext)) {
sub.unmatched(node);
continue;
}
sub.add(node);
count++;
}
return count > 0;
}
}
}