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The Bouncy Castle Crypto package is a Java implementation of cryptographic algorithms. This jar contains JCE provider and lightweight API for the Bouncy Castle Cryptography APIs for JDK 1.5 to JDK 1.8. Note: this package includes the NTRU encryption algorithms.

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package org.bouncycastle.pqc.math.linearalgebra;

import java.math.BigInteger;
import java.security.SecureRandom;

import org.bouncycastle.crypto.CryptoServicesRegistrar;
import org.bouncycastle.util.BigIntegers;

/**
 * Class of number-theory related functions for use with integers represented as
 * int's or BigInteger objects.
 */
public final class IntegerFunctions
{

    private static final BigInteger ZERO = BigInteger.valueOf(0);

    private static final BigInteger ONE = BigInteger.valueOf(1);

    private static final BigInteger TWO = BigInteger.valueOf(2);

    private static final BigInteger FOUR = BigInteger.valueOf(4);

    private static final int[] SMALL_PRIMES = {3, 5, 7, 11, 13, 17, 19, 23,
        29, 31, 37, 41};

    private static final long SMALL_PRIME_PRODUCT = 3L * 5 * 7 * 11 * 13 * 17
        * 19 * 23 * 29 * 31 * 37 * 41;

    private static SecureRandom sr = null;

    // the jacobi function uses this lookup table
    private static final int[] jacobiTable = {0, 1, 0, -1, 0, -1, 0, 1};

    private IntegerFunctions()
    {
        // empty
    }

    /**
     * Computes the value of the Jacobi symbol (A|B). The following properties
     * hold for the Jacobi symbol which makes it a very efficient way to
     * evaluate the Legendre symbol
     * 

* (A|B) = 0 IF gcd(A,B) > 1
* (-1|B) = 1 IF n = 1 (mod 1)
* (-1|B) = -1 IF n = 3 (mod 4)
* (A|B) (C|B) = (AC|B)
* (A|B) (A|C) = (A|CB)
* (A|B) = (C|B) IF A = C (mod B)
* (2|B) = 1 IF N = 1 OR 7 (mod 8)
* (2|B) = 1 IF N = 3 OR 5 (mod 8) * * @param A integer value * @param B integer value * @return value of the jacobi symbol (A|B) */ public static int jacobi(BigInteger A, BigInteger B) { BigInteger a, b, v; long k = 1; k = 1; // test trivial cases if (B.equals(ZERO)) { a = A.abs(); return a.equals(ONE) ? 1 : 0; } if (!A.testBit(0) && !B.testBit(0)) { return 0; } a = A; b = B; if (b.signum() == -1) { // b < 0 b = b.negate(); // b = -b if (a.signum() == -1) { k = -1; } } v = ZERO; while (!b.testBit(0)) { v = v.add(ONE); // v = v + 1 b = b.divide(TWO); // b = b/2 } if (v.testBit(0)) { k = k * jacobiTable[a.intValue() & 7]; } if (a.signum() < 0) { // a < 0 if (b.testBit(1)) { k = -k; // k = -k } a = a.negate(); // a = -a } // main loop while (a.signum() != 0) { v = ZERO; while (!a.testBit(0)) { // a is even v = v.add(ONE); a = a.divide(TWO); } if (v.testBit(0)) { k = k * jacobiTable[b.intValue() & 7]; } if (a.compareTo(b) < 0) { // a < b // swap and correct intermediate result BigInteger x = a; a = b; b = x; if (a.testBit(1) && b.testBit(1)) { k = -k; } } a = a.subtract(b); } return b.equals(ONE) ? (int)k : 0; } /** * Computes the square root of a BigInteger modulo a prime employing the * Shanks-Tonelli algorithm. * * @param a value out of which we extract the square root * @param p prime modulus that determines the underlying field * @return a number b such that b2 = a (mod p) if * a is a quadratic residue modulo p. * @throws IllegalArgumentException if a is a quadratic non-residue modulo p */ public static BigInteger ressol(BigInteger a, BigInteger p) throws IllegalArgumentException { BigInteger v = null; if (a.compareTo(ZERO) < 0) { a = a.add(p); } if (a.equals(ZERO)) { return ZERO; } if (p.equals(TWO)) { return a; } // p = 3 mod 4 if (p.testBit(0) && p.testBit(1)) { if (jacobi(a, p) == 1) { // a quadr. residue mod p v = p.add(ONE); // v = p+1 v = v.shiftRight(2); // v = v/4 return a.modPow(v, p); // return a^v mod p // return --> a^((p+1)/4) mod p } throw new IllegalArgumentException("No quadratic residue: " + a + ", " + p); } long t = 0; // initialization // compute k and s, where p = 2^s (2k+1) +1 BigInteger k = p.subtract(ONE); // k = p-1 long s = 0; while (!k.testBit(0)) { // while k is even s++; // s = s+1 k = k.shiftRight(1); // k = k/2 } k = k.subtract(ONE); // k = k - 1 k = k.shiftRight(1); // k = k/2 // initial values BigInteger r = a.modPow(k, p); // r = a^k mod p BigInteger n = r.multiply(r).remainder(p); // n = r^2 % p n = n.multiply(a).remainder(p); // n = n * a % p r = r.multiply(a).remainder(p); // r = r * a %p if (n.equals(ONE)) { return r; } // non-quadratic residue BigInteger z = TWO; // z = 2 while (jacobi(z, p) == 1) { // while z quadratic residue z = z.add(ONE); // z = z + 1 } v = k; v = v.multiply(TWO); // v = 2k v = v.add(ONE); // v = 2k + 1 BigInteger c = z.modPow(v, p); // c = z^v mod p // iteration while (n.compareTo(ONE) == 1) { // n > 1 k = n; // k = n t = s; // t = s s = 0; while (!k.equals(ONE)) { // k != 1 k = k.multiply(k).mod(p); // k = k^2 % p s++; // s = s + 1 } t -= s; // t = t - s if (t == 0) { throw new IllegalArgumentException("No quadratic residue: " + a + ", " + p); } v = ONE; for (long i = 0; i < t - 1; i++) { v = v.shiftLeft(1); // v = 1 * 2^(t - 1) } c = c.modPow(v, p); // c = c^v mod p r = r.multiply(c).remainder(p); // r = r * c % p c = c.multiply(c).remainder(p); // c = c^2 % p n = n.multiply(c).mod(p); // n = n * c % p } return r; } /** * Computes the greatest common divisor of the two specified integers * * @param u - first integer * @param v - second integer * @return gcd(a, b) */ public static int gcd(int u, int v) { return BigInteger.valueOf(u).gcd(BigInteger.valueOf(v)).intValue(); } /** * Extended euclidian algorithm (computes gcd and representation). * * @param a the first integer * @param b the second integer * @return (g,u,v), where g = gcd(abs(a),abs(b)) = ua + vb */ public static int[] extGCD(int a, int b) { BigInteger ba = BigInteger.valueOf(a); BigInteger bb = BigInteger.valueOf(b); BigInteger[] bresult = extgcd(ba, bb); int[] result = new int[3]; result[0] = bresult[0].intValue(); result[1] = bresult[1].intValue(); result[2] = bresult[2].intValue(); return result; } public static BigInteger divideAndRound(BigInteger a, BigInteger b) { if (a.signum() < 0) { return divideAndRound(a.negate(), b).negate(); } if (b.signum() < 0) { return divideAndRound(a, b.negate()).negate(); } return a.shiftLeft(1).add(b).divide(b.shiftLeft(1)); } public static BigInteger[] divideAndRound(BigInteger[] a, BigInteger b) { BigInteger[] out = new BigInteger[a.length]; for (int i = 0; i < a.length; i++) { out[i] = divideAndRound(a[i], b); } return out; } /** * Compute the smallest integer that is greater than or equal to the * logarithm to the base 2 of the given BigInteger. * * @param a the integer * @return ceil[log(a)] */ public static int ceilLog(BigInteger a) { int result = 0; BigInteger p = ONE; while (p.compareTo(a) < 0) { result++; p = p.shiftLeft(1); } return result; } /** * Compute the smallest integer that is greater than or equal to the * logarithm to the base 2 of the given integer. * * @param a the integer * @return ceil[log(a)] */ public static int ceilLog(int a) { int log = 0; int i = 1; while (i < a) { i <<= 1; log++; } return log; } /** * Compute ceil(log_256 n), the number of bytes needed to encode * the integer n. * * @param n the integer * @return the number of bytes needed to encode n */ public static int ceilLog256(int n) { if (n == 0) { return 1; } int m; if (n < 0) { m = -n; } else { m = n; } int d = 0; while (m > 0) { d++; m >>>= 8; } return d; } /** * Compute ceil(log_256 n), the number of bytes needed to encode * the long integer n. * * @param n the long integer * @return the number of bytes needed to encode n */ public static int ceilLog256(long n) { if (n == 0) { return 1; } long m; if (n < 0) { m = -n; } else { m = n; } int d = 0; while (m > 0) { d++; m >>>= 8; } return d; } /** * Compute the integer part of the logarithm to the base 2 of the given * integer. * * @param a the integer * @return floor[log(a)] */ public static int floorLog(BigInteger a) { int result = -1; BigInteger p = ONE; while (p.compareTo(a) <= 0) { result++; p = p.shiftLeft(1); } return result; } /** * Compute the integer part of the logarithm to the base 2 of the given * integer. * * @param a the integer * @return floor[log(a)] */ public static int floorLog(int a) { int h = 0; if (a <= 0) { return -1; } int p = a >>> 1; while (p > 0) { h++; p >>>= 1; } return h; } /** * Compute the largest h with 2^h | a if a!=0. * * @param a an integer * @return the largest h with 2^h | a if a!=0, * 0 otherwise */ public static int maxPower(int a) { int h = 0; if (a != 0) { int p = 1; while ((a & p) == 0) { h++; p <<= 1; } } return h; } /** * @param a an integer * @return the number of ones in the binary representation of an integer * a */ public static int bitCount(int a) { int h = 0; while (a != 0) { h += a & 1; a >>>= 1; } return h; } /** * determines the order of g modulo p, p prime and 1 < g < p. This algorithm * is only efficient for small p (see X9.62-1998, p. 68). * * @param g an integer with 1 < g < p * @param p a prime * @return the order k of g (that is k is the smallest integer with * gk = 1 mod p */ public static int order(int g, int p) { int b, j; b = g % p; // Reduce g mod p first. j = 1; // Check whether g == 0 mod p (avoiding endless loop). if (b == 0) { throw new IllegalArgumentException(g + " is not an element of Z/(" + p + "Z)^*; it is not meaningful to compute its order."); } // Compute the order of g mod p: while (b != 1) { b *= g; b %= p; if (b < 0) { b += p; } j++; } return j; } /** * Reduces an integer into a given interval * * @param n - the integer * @param begin - left bound of the interval * @param end - right bound of the interval * @return n reduced into [begin,end] */ public static BigInteger reduceInto(BigInteger n, BigInteger begin, BigInteger end) { return n.subtract(begin).mod(end.subtract(begin)).add(begin); } /** * Compute ae. * * @param a the base * @param e the exponent * @return ae */ public static int pow(int a, int e) { int result = 1; while (e > 0) { if ((e & 1) == 1) { result *= a; } a *= a; e >>>= 1; } return result; } /** * Compute ae. * * @param a the base * @param e the exponent * @return ae */ public static long pow(long a, int e) { long result = 1; while (e > 0) { if ((e & 1) == 1) { result *= a; } a *= a; e >>>= 1; } return result; } /** * Compute ae mod n. * * @param a the base * @param e the exponent * @param n the modulus * @return ae mod n */ public static int modPow(int a, int e, int n) { if (n <= 0 || (n * n) > Integer.MAX_VALUE || e < 0) { return 0; } int result = 1; a = (a % n + n) % n; while (e > 0) { if ((e & 1) == 1) { result = (result * a) % n; } a = (a * a) % n; e >>>= 1; } return result; } /** * Extended euclidian algorithm (computes gcd and representation). * * @param a - the first integer * @param b - the second integer * @return (d,u,v), where d = gcd(a,b) = ua + vb */ public static BigInteger[] extgcd(BigInteger a, BigInteger b) { BigInteger u = ONE; BigInteger v = ZERO; BigInteger d = a; if (b.signum() != 0) { BigInteger v1 = ZERO; BigInteger v3 = b; while (v3.signum() != 0) { BigInteger[] tmp = d.divideAndRemainder(v3); BigInteger q = tmp[0]; BigInteger t3 = tmp[1]; BigInteger t1 = u.subtract(q.multiply(v1)); u = v1; d = v3; v1 = t1; v3 = t3; } v = d.subtract(a.multiply(u)).divide(b); } return new BigInteger[]{d, u, v}; } /** * Computation of the least common multiple of a set of BigIntegers. * * @param numbers - the set of numbers * @return the lcm(numbers) */ public static BigInteger leastCommonMultiple(BigInteger[] numbers) { int n = numbers.length; BigInteger result = numbers[0]; for (int i = 1; i < n; i++) { BigInteger gcd = result.gcd(numbers[i]); result = result.multiply(numbers[i]).divide(gcd); } return result; } /** * Returns a long integer whose value is (a mod m). This method * differs from % in that it always returns a non-negative * integer. * * @param a value on which the modulo operation has to be performed. * @param m the modulus. * @return a mod m */ public static long mod(long a, long m) { long result = a % m; if (result < 0) { result += m; } return result; } /** * Computes the modular inverse of an integer a * * @param a - the integer to invert * @param mod - the modulus * @return a-1 mod n */ public static int modInverse(int a, int mod) { return BigInteger.valueOf(a).modInverse(BigInteger.valueOf(mod)) .intValue(); } /** * Computes the modular inverse of an integer a * * @param a - the integer to invert * @param mod - the modulus * @return a-1 mod n */ public static long modInverse(long a, long mod) { return BigInteger.valueOf(a).modInverse(BigInteger.valueOf(mod)) .longValue(); } /** * Tests whether an integer a is power of another integer * p. * * @param a - the first integer * @param p - the second integer * @return n if a = p^n or -1 otherwise */ public static int isPower(int a, int p) { if (a <= 0) { return -1; } int n = 0; int d = a; while (d > 1) { if (d % p != 0) { return -1; } d /= p; n++; } return n; } /** * Find and return the least non-trivial divisor of an integer a. * * @param a - the integer * @return divisor p >1 or 1 if a = -1,0,1 */ public static int leastDiv(int a) { if (a < 0) { a = -a; } if (a == 0) { return 1; } if ((a & 1) == 0) { return 2; } int p = 3; while (p <= (a / p)) { if ((a % p) == 0) { return p; } p += 2; } return a; } /** * Miller-Rabin-Test, determines wether the given integer is probably prime * or composite. This method returns true if the given integer is * prime with probability 1 - 2-20. * * @param n the integer to test for primality * @return true if the given integer is prime with probability * 2-100, false otherwise */ public static boolean isPrime(int n) { if (n < 2) { return false; } if (n == 2) { return true; } if ((n & 1) == 0) { return false; } if (n < 42) { for (int i = 0; i < SMALL_PRIMES.length; i++) { if (n == SMALL_PRIMES[i]) { return true; } } } if ((n % 3 == 0) || (n % 5 == 0) || (n % 7 == 0) || (n % 11 == 0) || (n % 13 == 0) || (n % 17 == 0) || (n % 19 == 0) || (n % 23 == 0) || (n % 29 == 0) || (n % 31 == 0) || (n % 37 == 0) || (n % 41 == 0)) { return false; } return BigInteger.valueOf(n).isProbablePrime(20); } /** * Short trial-division test to find out whether a number is not prime. This * test is usually used before a Miller-Rabin primality test. * * @param candidate the number to test * @return true if the number has no factor of the tested primes, * false if the number is definitely composite */ public static boolean passesSmallPrimeTest(BigInteger candidate) { final int[] smallPrime = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997, 1009, 1013, 1019, 1021, 1031, 1033, 1039, 1049, 1051, 1061, 1063, 1069, 1087, 1091, 1093, 1097, 1103, 1109, 1117, 1123, 1129, 1151, 1153, 1163, 1171, 1181, 1187, 1193, 1201, 1213, 1217, 1223, 1229, 1231, 1237, 1249, 1259, 1277, 1279, 1283, 1289, 1291, 1297, 1301, 1303, 1307, 1319, 1321, 1327, 1361, 1367, 1373, 1381, 1399, 1409, 1423, 1427, 1429, 1433, 1439, 1447, 1451, 1453, 1459, 1471, 1481, 1483, 1487, 1489, 1493, 1499}; for (int i = 0; i < smallPrime.length; i++) { if (candidate.mod(BigInteger.valueOf(smallPrime[i])).equals( ZERO)) { return false; } } return true; } /** * Returns the largest prime smaller than the given integer * * @param n - upper bound * @return the largest prime smaller than n, or 1 if * n <= 2 */ public static int nextSmallerPrime(int n) { if (n <= 2) { return 1; } if (n == 3) { return 2; } if ((n & 1) == 0) { n--; } else { n -= 2; } while (n > 3 && !isPrime(n)) { n -= 2; } return n; } /** * Compute the next probable prime greater than n with the * specified certainty. * * @param n a integer number * @param certainty the certainty that the generated number is prime * @return the next prime greater than n */ public static BigInteger nextProbablePrime(BigInteger n, int certainty) { if (n.signum() < 0 || n.signum() == 0 || n.equals(ONE)) { return TWO; } BigInteger result = n.add(ONE); // Ensure an odd number if (!result.testBit(0)) { result = result.add(ONE); } while (true) { // Do cheap "pre-test" if applicable if (result.bitLength() > 6) { long r = result.remainder( BigInteger.valueOf(SMALL_PRIME_PRODUCT)).longValue(); if ((r % 3 == 0) || (r % 5 == 0) || (r % 7 == 0) || (r % 11 == 0) || (r % 13 == 0) || (r % 17 == 0) || (r % 19 == 0) || (r % 23 == 0) || (r % 29 == 0) || (r % 31 == 0) || (r % 37 == 0) || (r % 41 == 0)) { result = result.add(TWO); continue; // Candidate is composite; try another } } // All candidates of bitLength 2 and 3 are prime by this point if (result.bitLength() < 4) { return result; } // The expensive test if (result.isProbablePrime(certainty)) { return result; } result = result.add(TWO); } } /** * Compute the next probable prime greater than n with the default * certainty (20). * * @param n a integer number * @return the next prime greater than n */ public static BigInteger nextProbablePrime(BigInteger n) { return nextProbablePrime(n, 20); } /** * Computes the next prime greater than n. * * @param n a integer number * @return the next prime greater than n */ public static BigInteger nextPrime(long n) { long i; boolean found = false; long result = 0; if (n <= 1) { return BigInteger.valueOf(2); } if (n == 2) { return BigInteger.valueOf(3); } for (i = n + 1 + (n & 1); (i <= n << 1) && !found; i += 2) { for (long j = 3; (j <= i >> 1) && !found; j += 2) { if (i % j == 0) { found = true; } } if (found) { found = false; } else { result = i; found = true; } } return BigInteger.valueOf(result); } /** * Computes the binomial coefficient (n|t) ("n over t"). Formula: *

    *
  • if n !=0 and t != 0 then (n|t) = Mult(i=1, t): (n-(i-1))/i
  • *
  • if t = 0 then (n|t) = 1
  • *
  • if n = 0 and t > 0 then (n|t) = 0
  • *
* * @param n - the "upper" integer * @param t - the "lower" integer * @return the binomialcoefficient "n over t" as BigInteger */ public static BigInteger binomial(int n, int t) { BigInteger result = ONE; if (n == 0) { if (t == 0) { return result; } return ZERO; } // the property (n|t) = (n|n-t) be used to reduce numbers of operations if (t > (n >>> 1)) { t = n - t; } for (int i = 1; i <= t; i++) { result = (result.multiply(BigInteger.valueOf(n - (i - 1)))) .divide(BigInteger.valueOf(i)); } return result; } public static BigInteger randomize(BigInteger upperBound) { if (sr == null) { sr = CryptoServicesRegistrar.getSecureRandom(); } return randomize(upperBound, sr); } public static BigInteger randomize(BigInteger upperBound, SecureRandom prng) { int blen = upperBound.bitLength(); BigInteger randomNum = BigInteger.valueOf(0); if (prng == null) { prng = sr != null ? sr : CryptoServicesRegistrar.getSecureRandom(); } for (int i = 0; i < 20; i++) { randomNum = BigIntegers.createRandomBigInteger(blen, prng); if (randomNum.compareTo(upperBound) < 0) { return randomNum; } } return randomNum.mod(upperBound); } /** * Extract the truncated square root of a BigInteger. * * @param a - value out of which we extract the square root * @return the truncated square root of a */ public static BigInteger squareRoot(BigInteger a) { int bl; BigInteger result, remainder, b; if (a.compareTo(ZERO) < 0) { throw new ArithmeticException( "cannot extract root of negative number" + a + "."); } bl = a.bitLength(); result = ZERO; remainder = ZERO; // if the bit length is odd then extra step if ((bl & 1) != 0) { result = result.add(ONE); bl--; } while (bl > 0) { remainder = remainder.multiply(FOUR); remainder = remainder.add(BigInteger.valueOf((a.testBit(--bl) ? 2 : 0) + (a.testBit(--bl) ? 1 : 0))); b = result.multiply(FOUR).add(ONE); result = result.multiply(TWO); if (remainder.compareTo(b) != -1) { result = result.add(ONE); remainder = remainder.subtract(b); } } return result; } /** * Takes an approximation of the root from an integer base, using newton's * algorithm * * @param base the base to take the root from * @param root the root, for example 2 for a square root */ public static float intRoot(int base, int root) { float gNew = base / root; float gOld = 0; int counter = 0; while (Math.abs(gOld - gNew) > 0.0001) { float gPow = floatPow(gNew, root); while (Float.isInfinite(gPow)) { gNew = (gNew + gOld) / 2; gPow = floatPow(gNew, root); } counter += 1; gOld = gNew; gNew = gOld - (gPow - base) / (root * floatPow(gOld, root - 1)); } return gNew; } /** * int power of a base float, only use for small ints * * @param f base float * @param i power to be raised to. * @return int power i of f */ public static float floatPow(float f, int i) { float g = 1; for (; i > 0; i--) { g *= f; } return g; } /** * calculate the logarithm to the base 2. * * @param x any double value * @return log_2(x) * @deprecated use MathFunctions.log(double) instead */ public static double log(double x) { if (x > 0 && x < 1) { double d = 1 / x; double result = -log(d); return result; } int tmp = 0; double tmp2 = 1; double d = x; while (d > 2) { d = d / 2; tmp += 1; tmp2 *= 2; } double rem = x / tmp2; rem = logBKM(rem); return tmp + rem; } /** * calculate the logarithm to the base 2. * * @param x any long value >=1 * @return log_2(x) * @deprecated use MathFunctions.log(long) instead */ public static double log(long x) { int tmp = floorLog(BigInteger.valueOf(x)); long tmp2 = 1 << tmp; double rem = (double)x / (double)tmp2; rem = logBKM(rem); return tmp + rem; } /** * BKM Algorithm to calculate logarithms to the base 2. * * @param arg a double value with 1<= arg<= 4.768462058 * @return log_2(arg) * @deprecated use MathFunctions.logBKM(double) instead */ private static double logBKM(double arg) { double ae[] = // A_e[k] = log_2 (1 + 0.5^k) { 1.0000000000000000000000000000000000000000000000000000000000000000000000000000, 0.5849625007211561814537389439478165087598144076924810604557526545410982276485, 0.3219280948873623478703194294893901758648313930245806120547563958159347765589, 0.1699250014423123629074778878956330175196288153849621209115053090821964552970, 0.0874628412503394082540660108104043540112672823448206881266090643866965081686, 0.0443941193584534376531019906736094674630459333742491317685543002674288465967, 0.0223678130284545082671320837460849094932677948156179815932199216587899627785, 0.0112272554232541203378805844158839407281095943600297940811823651462712311786, 0.0056245491938781069198591026740666017211096815383520359072957784732489771013, 0.0028150156070540381547362547502839489729507927389771959487826944878598909400, 0.0014081943928083889066101665016890524233311715793462235597709051792834906001, 0.0007042690112466432585379340422201964456668872087249334581924550139514213168, 0.0003521774803010272377989609925281744988670304302127133979341729842842377649, 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0.0000000000000000000001527512790591677515976780735407368332862218276873443537, 0.0000000000000000000000763756395295838757988410584167137033767056170417508383, 0.0000000000000000000000381878197647919378994210346199431733717514843471513618, 0.0000000000000000000000190939098823959689497106436628681671067254111334889005, 0.0000000000000000000000095469549411979844748553534196582286585751228071408728, 0.0000000000000000000000047734774705989922374276846068851506055906657137209047, 0.0000000000000000000000023867387352994961187138442777065843718711089344045782, 0.0000000000000000000000011933693676497480593569226324192944532044984865894525, 0.0000000000000000000000005966846838248740296784614396011477934194852481410926, 0.0000000000000000000000002983423419124370148392307506484490384140516252814304, 0.0000000000000000000000001491711709562185074196153830361933046331030629430117, 0.0000000000000000000000000745855854781092537098076934460888486730708440475045, 0.0000000000000000000000000372927927390546268549038472050424734256652501673274, 0.0000000000000000000000000186463963695273134274519237230207489851150821191330, 0.0000000000000000000000000093231981847636567137259618916352525606281553180093, 0.0000000000000000000000000046615990923818283568629809533488457973317312233323, 0.0000000000000000000000000023307995461909141784314904785572277779202790023236, 0.0000000000000000000000000011653997730954570892157452397493151087737428485431, 0.0000000000000000000000000005826998865477285446078726199923328593402722606924, 0.0000000000000000000000000002913499432738642723039363100255852559084863397344, 0.0000000000000000000000000001456749716369321361519681550201473345138307215067, 0.0000000000000000000000000000728374858184660680759840775119123438968122488047, 0.0000000000000000000000000000364187429092330340379920387564158411083803465567, 0.0000000000000000000000000000182093714546165170189960193783228378441837282509, 0.0000000000000000000000000000091046857273082585094980096891901482445902524441, 0.0000000000000000000000000000045523428636541292547490048446022564529197237262, 0.0000000000000000000000000000022761714318270646273745024223029238091160103901}; int n = 53; double x = 1; double y = 0; double z; double s = 1; int k; for (k = 0; k < n; k++) { z = x + x * s; if (z <= arg) { x = z; y += ae[k]; } s *= 0.5; } return y; } public static boolean isIncreasing(int[] a) { for (int i = 1; i < a.length; i++) { if (a[i - 1] >= a[i]) { System.out.println("a[" + (i - 1) + "] = " + a[i - 1] + " >= " + a[i] + " = a[" + i + "]"); return false; } } return true; } public static byte[] integerToOctets(BigInteger val) { byte[] valBytes = val.abs().toByteArray(); // check whether the array includes a sign bit if ((val.bitLength() & 7) != 0) { return valBytes; } // get rid of the sign bit (first byte) byte[] tmp = new byte[val.bitLength() >> 3]; System.arraycopy(valBytes, 1, tmp, 0, tmp.length); return tmp; } public static BigInteger octetsToInteger(byte[] data, int offset, int length) { byte[] val = new byte[length + 1]; val[0] = 0; System.arraycopy(data, offset, val, 1, length); return new BigInteger(val); } public static BigInteger octetsToInteger(byte[] data) { return octetsToInteger(data, 0, data.length); } }




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