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Groovy Eclipse Compiler wrapped for Batch Use from Maven
/*
* Licensed to the Apache Software Foundation (ASF) under one
* or more contributor license agreements. See the NOTICE file
* distributed with this work for additional information
* regarding copyright ownership. The ASF licenses this file
* to you under the Apache License, Version 2.0 (the
* "License"); you may not use this file except in compliance
* with the License. You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing,
* software distributed under the License is distributed on an
* "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
* KIND, either express or implied. See the License for the
* specific language governing permissions and limitations
* under the License.
*/
package org.codehaus.groovy.runtime;
import groovy.lang.GroovyRuntimeException;
import org.codehaus.groovy.runtime.typehandling.DefaultTypeTransformation;
import java.io.Serializable;
import java.util.Comparator;
/**
* Compares two objects using Groovy's friendly comparison algorithm, i.e.
* handles nulls gracefully (nul being less than everything else) and
* performs numeric type coercion if required.
*/
public class NumberAwareComparator implements Comparator, Serializable {
private static final long serialVersionUID = 9017657289076651660L;
public int compare(T o1, T o2) {
try {
return DefaultTypeTransformation.compareTo(o1, o2);
} catch (ClassCastException | IllegalArgumentException | GroovyRuntimeException cce) {
/* ignore */
}
// since the object does not have a valid compareTo method
// we compare using the hashcodes. null cases are handled by
// DefaultTypeTransformation.compareTo
// This is not exactly a mathematical valid approach, since we compare object
// that cannot be compared. To avoid strange side effects we do a pseudo order
// using hashcodes, but without equality. Since then an x and y with the same
// hashcodes will behave different depending on if we compare x with y or
// x with y, the result might be unstable as well. Setting x and y to equal
// may mean the removal of x or y in a sorting operation, which we don't want.
int x1 = o1.hashCode();
int x2 = o2.hashCode();
if (x1 == x2 && o1.equals(o2)) return 0;
if (x1 > x2) return 1;
return -1;
}
}
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