
org.sonar.l10n.java.rules.squid.S1182.html Maven / Gradle / Ivy
The usual convention for Object.clone()
according to Oracle's Javadoc is that:
x.clone() != x
x.clone().getClass() == x.getClass()
x.clone().equals(x)
Obtaining the object that will be returned by calling super.clone()
helps to satisfy those invariants:
super.clone()
returns a new object instance
super.clone()
returns an object of the same type as the one clone()
was called on
Object.clone()
performs a shallow copy of the object's state
For example, the following code:
class BaseClass implements Cloneable {
@Override
public Object clone() throws CloneNotSupportedException { // Non-Compliant - should return the super.clone() instance
return new BaseClass();
}
}
class DerivedClass extends BaseClass implements Cloneable {
/* Does not override clone() */
public void sayHello() {
System.out.println("Hello, world!");
}
}
class Application {
public static void main(String[] args) throws Exception {
DerivedClass instance = new DerivedClass();
((DerivedClass) instance.clone()).sayHello(); // Throws a ClassCastException because invariant #2 is violated
}
}
should be refactored into:
class BaseClass implements Cloneable {
@Override
public Object clone() throws CloneNotSupportedException { // Compliant
return super.clone();
}
}
class DerivedClass extends BaseClass implements Cloneable {
/* Does not override clone() */
public void sayHello() {
System.out.println("Hello, world!");
}
}
class Application {
public static void main(String[] args) throws Exception {
DerivedClass instance = new DerivedClass();
((DerivedClass) instance.clone()).sayHello(); // Displays "Hello, world!" as expected. Invariant #2 is satisfied
}
}
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