org.elasticsearch.hadoop.util.regex.Regex Maven / Gradle / Ivy
/*
* Licensed to Elasticsearch under one or more contributor
* license agreements. See the NOTICE file distributed with
* this work for additional information regarding copyright
* ownership. Elasticsearch licenses this file to you under
* the Apache License, Version 2.0 (the "License"); you may
* not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing,
* software distributed under the License is distributed on an
* "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
* KIND, either express or implied. See the License for the
* specific language governing permissions and limitations
* under the License.
*/
package org.elasticsearch.hadoop.util.regex;
import java.util.Collection;
import java.util.List;
// Taken from Elasticsearch core
public class Regex {
/**
* Is the str a simple match pattern.
*/
public static boolean isSimpleMatchPattern(String str) {
return str.indexOf('*') != -1;
}
public static boolean isMatchAllPattern(String str) {
return str.equals("*");
}
/**
* Match a String against the given pattern, supporting the following simple
* pattern styles: "xxx*", "*xxx", "*xxx*" and "xxx*yyy" matches (with an
* arbitrary number of pattern parts), as well as direct equality.
*
* @param pattern the pattern to match against
* @param str the String to match
* @return whether the String matches the given pattern
*/
public static boolean simpleMatch(String pattern, String str) {
if (pattern == null || str == null) {
return false;
}
int firstIndex = pattern.indexOf('*');
if (firstIndex == -1) {
return pattern.equals(str);
}
if (firstIndex == 0) {
if (pattern.length() == 1) {
return true;
}
int nextIndex = pattern.indexOf('*', firstIndex + 1);
if (nextIndex == -1) {
return str.endsWith(pattern.substring(1));
}
else if (nextIndex == 1) {
// Double wildcard "**" - skipping the first "*"
return simpleMatch(pattern.substring(1), str);
}
String part = pattern.substring(1, nextIndex);
int partIndex = str.indexOf(part);
while (partIndex != -1) {
if (simpleMatch(pattern.substring(nextIndex), str.substring(partIndex + part.length()))) {
return true;
}
partIndex = str.indexOf(part, partIndex + 1);
}
return false;
}
return (str.length() >= firstIndex && pattern.substring(0, firstIndex).equals(str.substring(0, firstIndex)) && simpleMatch(
pattern.substring(firstIndex), str.substring(firstIndex)));
}
/**
* Match a String against the given patterns, supporting the following simple
* pattern styles: "xxx*", "*xxx", "*xxx*" and "xxx*yyy" matches (with an
* arbitrary number of pattern parts), as well as direct equality.
*
* @param patterns the patterns to match against
* @param str the String to match
* @return whether the String matches any of the given patterns
*/
public static boolean simpleMatch(Collection patterns, String str) {
if (patterns != null) {
for (String pattern : patterns) {
if (simpleMatch(pattern, str)) {
return true;
}
}
}
return false;
}
public static boolean simpleMatch(List patterns, String[] types) {
if (patterns != null && types != null) {
for (String type : types) {
for (String pattern : patterns) {
if (simpleMatch(pattern, type)) {
return true;
}
}
}
}
return false;
}
}